RE: iSCSI: Marker negotiation - draft 11

[Michael Schoberg <michael_schoberg@cnt.com>]

[(MI +  8) * n - 8] 

This is the formula in the draft.  I'm just wondering how a 2048 byte
interval results in a marker at location 1032.  Using the above formula for
n = 0 .. X:

n = 0, 		-8
n = 1,		512
n = 2, 		1032
n = 3,		1552
...

That doesn't look like a 2048 byte interval to me.  Perhaps someone could
explain the math. 

You may want to describe the formula a little clearer:

	Start of marker (byte location) = ((MI + 8) * n) - 8 

	[n] is an incrementing integer describing the n'th 
	  marker inserted into the TCP output stream.  n > 0
	[MI] is the negotiated marker interval value in bytes.



Where does this come from?

	"512+8+512=1032 (-1 since it starts at 0) = 1031" 

What formula are you using?



:-----Original Message-----
:From: John Hufferd [mailto:hufferd@us.ibm.com]
:Sent: Tuesday, March 12, 2002 12:45 PM
:To: Michael Schoberg
:Cc: IPS Reflector (E-mail)
:Subject: Re: iSCSI: Marker negotiation - draft 11
:
:
:
:512+8+512=1032 (-1 since it starts at 0) = 1031.
:
:...the first marker will be placed in the TCP stream as if  
:the Marker-less
:interval had included markers.
:
:.
:.
:.
:John L. Hufferd
:Senior Technical Staff Member (STSM)
:IBM/SSG San Jose Ca
:Main Office (408) 256-0403, Tie: 276-0403,  eFax: (408) 904-4688
:Home Office (408) 997-6136, Cell: (408) 499-9702
:Internet address: hufferd@us.ibm.com
: